Sort List | Problem No. 148 | LeetCode

Given the head of a linked list, return the list after sorting it in ascending order.

Follow up: Can you sort the linked list in O(n logn) time and O(1) memory (i.e. constant space)?

Example 1:

Input: head = [4,2,1,3] Output: [1,2,3,4] Example 2:

Input: head = [-1,5,3,4,0] Output: [-1,0,3,4,5] Example 3:

Input: head = [] Output: []

Constraints:

The number of nodes in the list is in the range [0, 5 * 104]. -105 <= Node.val <= 105

class Solution {
public:
    ListNode* sortList(ListNode* head) {
        if (!head || !head->next)
            return head;
        ListNode* mid = getMid(head);
        ListNode* left = sortList(head);
        ListNode* right = sortList(mid);
        return merge(left, right);
    }

    ListNode* merge(ListNode* list1, ListNode* list2) {
        ListNode dummyHead(0);
        ListNode* ptr = &dummyHead;
        while (list1 && list2) {
            if (list1->val < list2->val) {
                ptr->next = list1;
                list1 = list1->next;
            } else {
                ptr->next = list2;
                list2 = list2->next;
            }
            ptr = ptr->next;
        }
        if(list1) ptr->next = list1;
        else ptr->next = list2;

        return dummyHead.next;
    }

    ListNode* getMid(ListNode* head) {
        ListNode* midPrev = nullptr;
        while (head && head->next) {
            midPrev = (midPrev == nullptr) ? head : midPrev->next;
            head = head->next->next;
        }
        ListNode* mid = midPrev->next;
        midPrev->next = nullptr;
        return mid;
    }
};